Math 122 Discussion BoardNow we proceed to solve the inequality "and", the exercise to solve this then:4 2 + 4 16We must satisfy both restrictions at the same time. Such that 2 + 4 16 and also that 4 2 + 4. In the first case 2x + 16 must be less than or equal to 16 and in the second case that2 + 4x must be greater than or equal to 4. This represents a compound inequality and theresult of it is the intersection of both solutions.4 2 + 4 16 we will operate simultaneously the compound inequality4 2 4 16 2 we add -2 to both sides ...
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